Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 369, 812 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 369, 812 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 369, 812 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 369, 812 is 1.
HCF(369, 812) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 369, 812 is 1.
Step 1: Since 812 > 369, we apply the division lemma to 812 and 369, to get
812 = 369 x 2 + 74
Step 2: Since the reminder 369 ≠ 0, we apply division lemma to 74 and 369, to get
369 = 74 x 4 + 73
Step 3: We consider the new divisor 74 and the new remainder 73, and apply the division lemma to get
74 = 73 x 1 + 1
We consider the new divisor 73 and the new remainder 1, and apply the division lemma to get
73 = 1 x 73 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 369 and 812 is 1
Notice that 1 = HCF(73,1) = HCF(74,73) = HCF(369,74) = HCF(812,369) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 369, 812?
Answer: HCF of 369, 812 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 369, 812 using Euclid's Algorithm?
Answer: For arbitrary numbers 369, 812 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.