Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 397, 847 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 397, 847 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 397, 847 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 397, 847 is 1.
HCF(397, 847) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 397, 847 is 1.
Step 1: Since 847 > 397, we apply the division lemma to 847 and 397, to get
847 = 397 x 2 + 53
Step 2: Since the reminder 397 ≠ 0, we apply division lemma to 53 and 397, to get
397 = 53 x 7 + 26
Step 3: We consider the new divisor 53 and the new remainder 26, and apply the division lemma to get
53 = 26 x 2 + 1
We consider the new divisor 26 and the new remainder 1, and apply the division lemma to get
26 = 1 x 26 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 397 and 847 is 1
Notice that 1 = HCF(26,1) = HCF(53,26) = HCF(397,53) = HCF(847,397) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 397, 847?
Answer: HCF of 397, 847 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 397, 847 using Euclid's Algorithm?
Answer: For arbitrary numbers 397, 847 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.