Highest Common Factor of 462, 251, 237, 30 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 462, 251, 237, 30 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 462, 251, 237, 30 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 462, 251, 237, 30 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 462, 251, 237, 30 is 1.

HCF(462, 251, 237, 30) = 1

HCF of 462, 251, 237, 30 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 462, 251, 237, 30 is 1.

Highest Common Factor of 462,251,237,30 using Euclid's algorithm

Highest Common Factor of 462,251,237,30 is 1

Step 1: Since 462 > 251, we apply the division lemma to 462 and 251, to get

462 = 251 x 1 + 211

Step 2: Since the reminder 251 ≠ 0, we apply division lemma to 211 and 251, to get

251 = 211 x 1 + 40

Step 3: We consider the new divisor 211 and the new remainder 40, and apply the division lemma to get

211 = 40 x 5 + 11

We consider the new divisor 40 and the new remainder 11,and apply the division lemma to get

40 = 11 x 3 + 7

We consider the new divisor 11 and the new remainder 7,and apply the division lemma to get

11 = 7 x 1 + 4

We consider the new divisor 7 and the new remainder 4,and apply the division lemma to get

7 = 4 x 1 + 3

We consider the new divisor 4 and the new remainder 3,and apply the division lemma to get

4 = 3 x 1 + 1

We consider the new divisor 3 and the new remainder 1,and apply the division lemma to get

3 = 1 x 3 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 462 and 251 is 1

Notice that 1 = HCF(3,1) = HCF(4,3) = HCF(7,4) = HCF(11,7) = HCF(40,11) = HCF(211,40) = HCF(251,211) = HCF(462,251) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 237 > 1, we apply the division lemma to 237 and 1, to get

237 = 1 x 237 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 237 is 1

Notice that 1 = HCF(237,1) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 30 > 1, we apply the division lemma to 30 and 1, to get

30 = 1 x 30 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 30 is 1

Notice that 1 = HCF(30,1) .

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Frequently Asked Questions on HCF of 462, 251, 237, 30 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 462, 251, 237, 30?

Answer: HCF of 462, 251, 237, 30 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 462, 251, 237, 30 using Euclid's Algorithm?

Answer: For arbitrary numbers 462, 251, 237, 30 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.