Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 485, 647 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 485, 647 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 485, 647 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 485, 647 is 1.
HCF(485, 647) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 485, 647 is 1.
Step 1: Since 647 > 485, we apply the division lemma to 647 and 485, to get
647 = 485 x 1 + 162
Step 2: Since the reminder 485 ≠ 0, we apply division lemma to 162 and 485, to get
485 = 162 x 2 + 161
Step 3: We consider the new divisor 162 and the new remainder 161, and apply the division lemma to get
162 = 161 x 1 + 1
We consider the new divisor 161 and the new remainder 1, and apply the division lemma to get
161 = 1 x 161 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 485 and 647 is 1
Notice that 1 = HCF(161,1) = HCF(162,161) = HCF(485,162) = HCF(647,485) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 485, 647?
Answer: HCF of 485, 647 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 485, 647 using Euclid's Algorithm?
Answer: For arbitrary numbers 485, 647 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.