Highest Common Factor of 491, 255, 143, 127 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 491, 255, 143, 127 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 491, 255, 143, 127 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 491, 255, 143, 127 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 491, 255, 143, 127 is 1.

HCF(491, 255, 143, 127) = 1

HCF of 491, 255, 143, 127 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 491, 255, 143, 127 is 1.

Highest Common Factor of 491,255,143,127 using Euclid's algorithm

Highest Common Factor of 491,255,143,127 is 1

Step 1: Since 491 > 255, we apply the division lemma to 491 and 255, to get

491 = 255 x 1 + 236

Step 2: Since the reminder 255 ≠ 0, we apply division lemma to 236 and 255, to get

255 = 236 x 1 + 19

Step 3: We consider the new divisor 236 and the new remainder 19, and apply the division lemma to get

236 = 19 x 12 + 8

We consider the new divisor 19 and the new remainder 8,and apply the division lemma to get

19 = 8 x 2 + 3

We consider the new divisor 8 and the new remainder 3,and apply the division lemma to get

8 = 3 x 2 + 2

We consider the new divisor 3 and the new remainder 2,and apply the division lemma to get

3 = 2 x 1 + 1

We consider the new divisor 2 and the new remainder 1,and apply the division lemma to get

2 = 1 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 491 and 255 is 1

Notice that 1 = HCF(2,1) = HCF(3,2) = HCF(8,3) = HCF(19,8) = HCF(236,19) = HCF(255,236) = HCF(491,255) .


We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 143 > 1, we apply the division lemma to 143 and 1, to get

143 = 1 x 143 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 143 is 1

Notice that 1 = HCF(143,1) .


We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 127 > 1, we apply the division lemma to 127 and 1, to get

127 = 1 x 127 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 127 is 1

Notice that 1 = HCF(127,1) .

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Frequently Asked Questions on HCF of 491, 255, 143, 127 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 491, 255, 143, 127?

Answer: HCF of 491, 255, 143, 127 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 491, 255, 143, 127 using Euclid's Algorithm?

Answer: For arbitrary numbers 491, 255, 143, 127 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.