Highest Common Factor of 4913, 153 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 4913, 153 i.e. 17 the largest integer that leaves a remainder zero for all numbers.

HCF of 4913, 153 is 17 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 4913, 153 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 4913, 153 is 17.

HCF(4913, 153) = 17

HCF of 4913, 153 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 4913, 153 is 17.

Highest Common Factor of 4913,153 using Euclid's algorithm

Highest Common Factor of 4913,153 is 17

Step 1: Since 4913 > 153, we apply the division lemma to 4913 and 153, to get

4913 = 153 x 32 + 17

Step 2: Since the reminder 153 ≠ 0, we apply division lemma to 17 and 153, to get

153 = 17 x 9 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 17, the HCF of 4913 and 153 is 17

Notice that 17 = HCF(153,17) = HCF(4913,153) .

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Frequently Asked Questions on HCF of 4913, 153 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 4913, 153?

Answer: HCF of 4913, 153 is 17 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 4913, 153 using Euclid's Algorithm?

Answer: For arbitrary numbers 4913, 153 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.