Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 493, 578 i.e. 17 the largest integer that leaves a remainder zero for all numbers.
HCF of 493, 578 is 17 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 493, 578 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 493, 578 is 17.
HCF(493, 578) = 17
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 493, 578 is 17.
Step 1: Since 578 > 493, we apply the division lemma to 578 and 493, to get
578 = 493 x 1 + 85
Step 2: Since the reminder 493 ≠ 0, we apply division lemma to 85 and 493, to get
493 = 85 x 5 + 68
Step 3: We consider the new divisor 85 and the new remainder 68, and apply the division lemma to get
85 = 68 x 1 + 17
We consider the new divisor 68 and the new remainder 17, and apply the division lemma to get
68 = 17 x 4 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 17, the HCF of 493 and 578 is 17
Notice that 17 = HCF(68,17) = HCF(85,68) = HCF(493,85) = HCF(578,493) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 493, 578?
Answer: HCF of 493, 578 is 17 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 493, 578 using Euclid's Algorithm?
Answer: For arbitrary numbers 493, 578 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.