Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 497, 580 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 497, 580 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 497, 580 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 497, 580 is 1.
HCF(497, 580) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 497, 580 is 1.
Step 1: Since 580 > 497, we apply the division lemma to 580 and 497, to get
580 = 497 x 1 + 83
Step 2: Since the reminder 497 ≠ 0, we apply division lemma to 83 and 497, to get
497 = 83 x 5 + 82
Step 3: We consider the new divisor 83 and the new remainder 82, and apply the division lemma to get
83 = 82 x 1 + 1
We consider the new divisor 82 and the new remainder 1, and apply the division lemma to get
82 = 1 x 82 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 497 and 580 is 1
Notice that 1 = HCF(82,1) = HCF(83,82) = HCF(497,83) = HCF(580,497) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 497, 580?
Answer: HCF of 497, 580 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 497, 580 using Euclid's Algorithm?
Answer: For arbitrary numbers 497, 580 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.