# Highest Common Factor of 50, 58 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 50, 58 i.e. 2 the largest integer that leaves a remainder zero for all numbers.

HCF of 50, 58 is 2 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 50, 58 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 50, 58 is 2.

HCF(50, 58) = 2

## HCF of 50, 58 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 50, 58 is 2. ### Highest Common Factor of 50,58 is 2

Step 1: Since 58 > 50, we apply the division lemma to 58 and 50, to get

58 = 50 x 1 + 8

Step 2: Since the reminder 50 ≠ 0, we apply division lemma to 8 and 50, to get

50 = 8 x 6 + 2

Step 3: We consider the new divisor 8 and the new remainder 2, and apply the division lemma to get

8 = 2 x 4 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 2, the HCF of 50 and 58 is 2

Notice that 2 = HCF(8,2) = HCF(50,8) = HCF(58,50) .

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### Frequently Asked Questions on HCF of 50, 58 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 50, 58?

Answer: HCF of 50, 58 is 2 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 50, 58 using Euclid's Algorithm?

Answer: For arbitrary numbers 50, 58 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.