Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 507, 6545 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 507, 6545 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 507, 6545 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 507, 6545 is 1.
HCF(507, 6545) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 507, 6545 is 1.
Step 1: Since 6545 > 507, we apply the division lemma to 6545 and 507, to get
6545 = 507 x 12 + 461
Step 2: Since the reminder 507 ≠ 0, we apply division lemma to 461 and 507, to get
507 = 461 x 1 + 46
Step 3: We consider the new divisor 461 and the new remainder 46, and apply the division lemma to get
461 = 46 x 10 + 1
We consider the new divisor 46 and the new remainder 1, and apply the division lemma to get
46 = 1 x 46 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 507 and 6545 is 1
Notice that 1 = HCF(46,1) = HCF(461,46) = HCF(507,461) = HCF(6545,507) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 507, 6545?
Answer: HCF of 507, 6545 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 507, 6545 using Euclid's Algorithm?
Answer: For arbitrary numbers 507, 6545 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.