Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 5093, 222 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 5093, 222 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 5093, 222 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 5093, 222 is 1.
HCF(5093, 222) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 5093, 222 is 1.
Step 1: Since 5093 > 222, we apply the division lemma to 5093 and 222, to get
5093 = 222 x 22 + 209
Step 2: Since the reminder 222 ≠ 0, we apply division lemma to 209 and 222, to get
222 = 209 x 1 + 13
Step 3: We consider the new divisor 209 and the new remainder 13, and apply the division lemma to get
209 = 13 x 16 + 1
We consider the new divisor 13 and the new remainder 1, and apply the division lemma to get
13 = 1 x 13 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 5093 and 222 is 1
Notice that 1 = HCF(13,1) = HCF(209,13) = HCF(222,209) = HCF(5093,222) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 5093, 222?
Answer: HCF of 5093, 222 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 5093, 222 using Euclid's Algorithm?
Answer: For arbitrary numbers 5093, 222 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.