Highest Common Factor of 512, 445, 218, 143 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 512, 445, 218, 143 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 512, 445, 218, 143 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 512, 445, 218, 143 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 512, 445, 218, 143 is 1.

HCF(512, 445, 218, 143) = 1

HCF of 512, 445, 218, 143 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 512, 445, 218, 143 is 1.

Highest Common Factor of 512,445,218,143 using Euclid's algorithm

Highest Common Factor of 512,445,218,143 is 1

Step 1: Since 512 > 445, we apply the division lemma to 512 and 445, to get

512 = 445 x 1 + 67

Step 2: Since the reminder 445 ≠ 0, we apply division lemma to 67 and 445, to get

445 = 67 x 6 + 43

Step 3: We consider the new divisor 67 and the new remainder 43, and apply the division lemma to get

67 = 43 x 1 + 24

We consider the new divisor 43 and the new remainder 24,and apply the division lemma to get

43 = 24 x 1 + 19

We consider the new divisor 24 and the new remainder 19,and apply the division lemma to get

24 = 19 x 1 + 5

We consider the new divisor 19 and the new remainder 5,and apply the division lemma to get

19 = 5 x 3 + 4

We consider the new divisor 5 and the new remainder 4,and apply the division lemma to get

5 = 4 x 1 + 1

We consider the new divisor 4 and the new remainder 1,and apply the division lemma to get

4 = 1 x 4 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 512 and 445 is 1

Notice that 1 = HCF(4,1) = HCF(5,4) = HCF(19,5) = HCF(24,19) = HCF(43,24) = HCF(67,43) = HCF(445,67) = HCF(512,445) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 218 > 1, we apply the division lemma to 218 and 1, to get

218 = 1 x 218 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 218 is 1

Notice that 1 = HCF(218,1) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 143 > 1, we apply the division lemma to 143 and 1, to get

143 = 1 x 143 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 143 is 1

Notice that 1 = HCF(143,1) .

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Frequently Asked Questions on HCF of 512, 445, 218, 143 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 512, 445, 218, 143?

Answer: HCF of 512, 445, 218, 143 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 512, 445, 218, 143 using Euclid's Algorithm?

Answer: For arbitrary numbers 512, 445, 218, 143 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.