Highest Common Factor of 512, 743, 248, 213 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 512, 743, 248, 213 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 512, 743, 248, 213 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 512, 743, 248, 213 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 512, 743, 248, 213 is 1.

HCF(512, 743, 248, 213) = 1

HCF of 512, 743, 248, 213 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 512, 743, 248, 213 is 1.

Highest Common Factor of 512,743,248,213 using Euclid's algorithm

Highest Common Factor of 512,743,248,213 is 1

Step 1: Since 743 > 512, we apply the division lemma to 743 and 512, to get

743 = 512 x 1 + 231

Step 2: Since the reminder 512 ≠ 0, we apply division lemma to 231 and 512, to get

512 = 231 x 2 + 50

Step 3: We consider the new divisor 231 and the new remainder 50, and apply the division lemma to get

231 = 50 x 4 + 31

We consider the new divisor 50 and the new remainder 31,and apply the division lemma to get

50 = 31 x 1 + 19

We consider the new divisor 31 and the new remainder 19,and apply the division lemma to get

31 = 19 x 1 + 12

We consider the new divisor 19 and the new remainder 12,and apply the division lemma to get

19 = 12 x 1 + 7

We consider the new divisor 12 and the new remainder 7,and apply the division lemma to get

12 = 7 x 1 + 5

We consider the new divisor 7 and the new remainder 5,and apply the division lemma to get

7 = 5 x 1 + 2

We consider the new divisor 5 and the new remainder 2,and apply the division lemma to get

5 = 2 x 2 + 1

We consider the new divisor 2 and the new remainder 1,and apply the division lemma to get

2 = 1 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 512 and 743 is 1

Notice that 1 = HCF(2,1) = HCF(5,2) = HCF(7,5) = HCF(12,7) = HCF(19,12) = HCF(31,19) = HCF(50,31) = HCF(231,50) = HCF(512,231) = HCF(743,512) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 248 > 1, we apply the division lemma to 248 and 1, to get

248 = 1 x 248 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 248 is 1

Notice that 1 = HCF(248,1) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 213 > 1, we apply the division lemma to 213 and 1, to get

213 = 1 x 213 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 213 is 1

Notice that 1 = HCF(213,1) .

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Frequently Asked Questions on HCF of 512, 743, 248, 213 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 512, 743, 248, 213?

Answer: HCF of 512, 743, 248, 213 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 512, 743, 248, 213 using Euclid's Algorithm?

Answer: For arbitrary numbers 512, 743, 248, 213 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.