Highest Common Factor of 5165, 1952, 87656 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 5165, 1952, 87656 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 5165, 1952, 87656 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 5165, 1952, 87656 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 5165, 1952, 87656 is 1.

HCF(5165, 1952, 87656) = 1

HCF of 5165, 1952, 87656 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 5165, 1952, 87656 is 1.

Highest Common Factor of 5165,1952,87656 using Euclid's algorithm

Highest Common Factor of 5165,1952,87656 is 1

Step 1: Since 5165 > 1952, we apply the division lemma to 5165 and 1952, to get

5165 = 1952 x 2 + 1261

Step 2: Since the reminder 1952 ≠ 0, we apply division lemma to 1261 and 1952, to get

1952 = 1261 x 1 + 691

Step 3: We consider the new divisor 1261 and the new remainder 691, and apply the division lemma to get

1261 = 691 x 1 + 570

We consider the new divisor 691 and the new remainder 570,and apply the division lemma to get

691 = 570 x 1 + 121

We consider the new divisor 570 and the new remainder 121,and apply the division lemma to get

570 = 121 x 4 + 86

We consider the new divisor 121 and the new remainder 86,and apply the division lemma to get

121 = 86 x 1 + 35

We consider the new divisor 86 and the new remainder 35,and apply the division lemma to get

86 = 35 x 2 + 16

We consider the new divisor 35 and the new remainder 16,and apply the division lemma to get

35 = 16 x 2 + 3

We consider the new divisor 16 and the new remainder 3,and apply the division lemma to get

16 = 3 x 5 + 1

We consider the new divisor 3 and the new remainder 1,and apply the division lemma to get

3 = 1 x 3 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 5165 and 1952 is 1

Notice that 1 = HCF(3,1) = HCF(16,3) = HCF(35,16) = HCF(86,35) = HCF(121,86) = HCF(570,121) = HCF(691,570) = HCF(1261,691) = HCF(1952,1261) = HCF(5165,1952) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 87656 > 1, we apply the division lemma to 87656 and 1, to get

87656 = 1 x 87656 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 87656 is 1

Notice that 1 = HCF(87656,1) .

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Frequently Asked Questions on HCF of 5165, 1952, 87656 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 5165, 1952, 87656?

Answer: HCF of 5165, 1952, 87656 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 5165, 1952, 87656 using Euclid's Algorithm?

Answer: For arbitrary numbers 5165, 1952, 87656 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.