Highest Common Factor of 537, 352, 547 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 537, 352, 547 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 537, 352, 547 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 537, 352, 547 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 537, 352, 547 is 1.

HCF(537, 352, 547) = 1

HCF of 537, 352, 547 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 537, 352, 547 is 1.

Highest Common Factor of 537,352,547 using Euclid's algorithm

Highest Common Factor of 537,352,547 is 1

Step 1: Since 537 > 352, we apply the division lemma to 537 and 352, to get

537 = 352 x 1 + 185

Step 2: Since the reminder 352 ≠ 0, we apply division lemma to 185 and 352, to get

352 = 185 x 1 + 167

Step 3: We consider the new divisor 185 and the new remainder 167, and apply the division lemma to get

185 = 167 x 1 + 18

We consider the new divisor 167 and the new remainder 18,and apply the division lemma to get

167 = 18 x 9 + 5

We consider the new divisor 18 and the new remainder 5,and apply the division lemma to get

18 = 5 x 3 + 3

We consider the new divisor 5 and the new remainder 3,and apply the division lemma to get

5 = 3 x 1 + 2

We consider the new divisor 3 and the new remainder 2,and apply the division lemma to get

3 = 2 x 1 + 1

We consider the new divisor 2 and the new remainder 1,and apply the division lemma to get

2 = 1 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 537 and 352 is 1

Notice that 1 = HCF(2,1) = HCF(3,2) = HCF(5,3) = HCF(18,5) = HCF(167,18) = HCF(185,167) = HCF(352,185) = HCF(537,352) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 547 > 1, we apply the division lemma to 547 and 1, to get

547 = 1 x 547 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 547 is 1

Notice that 1 = HCF(547,1) .

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Frequently Asked Questions on HCF of 537, 352, 547 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 537, 352, 547?

Answer: HCF of 537, 352, 547 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 537, 352, 547 using Euclid's Algorithm?

Answer: For arbitrary numbers 537, 352, 547 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.