Highest Common Factor of 537, 487, 487, 31 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 537, 487, 487, 31 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 537, 487, 487, 31 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 537, 487, 487, 31 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 537, 487, 487, 31 is 1.

HCF(537, 487, 487, 31) = 1

HCF of 537, 487, 487, 31 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 537, 487, 487, 31 is 1.

Highest Common Factor of 537,487,487,31 using Euclid's algorithm

Highest Common Factor of 537,487,487,31 is 1

Step 1: Since 537 > 487, we apply the division lemma to 537 and 487, to get

537 = 487 x 1 + 50

Step 2: Since the reminder 487 ≠ 0, we apply division lemma to 50 and 487, to get

487 = 50 x 9 + 37

Step 3: We consider the new divisor 50 and the new remainder 37, and apply the division lemma to get

50 = 37 x 1 + 13

We consider the new divisor 37 and the new remainder 13,and apply the division lemma to get

37 = 13 x 2 + 11

We consider the new divisor 13 and the new remainder 11,and apply the division lemma to get

13 = 11 x 1 + 2

We consider the new divisor 11 and the new remainder 2,and apply the division lemma to get

11 = 2 x 5 + 1

We consider the new divisor 2 and the new remainder 1,and apply the division lemma to get

2 = 1 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 537 and 487 is 1

Notice that 1 = HCF(2,1) = HCF(11,2) = HCF(13,11) = HCF(37,13) = HCF(50,37) = HCF(487,50) = HCF(537,487) .


We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 487 > 1, we apply the division lemma to 487 and 1, to get

487 = 1 x 487 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 487 is 1

Notice that 1 = HCF(487,1) .


We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 31 > 1, we apply the division lemma to 31 and 1, to get

31 = 1 x 31 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 31 is 1

Notice that 1 = HCF(31,1) .

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Frequently Asked Questions on HCF of 537, 487, 487, 31 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 537, 487, 487, 31?

Answer: HCF of 537, 487, 487, 31 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 537, 487, 487, 31 using Euclid's Algorithm?

Answer: For arbitrary numbers 537, 487, 487, 31 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.