Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 558, 639 i.e. 9 the largest integer that leaves a remainder zero for all numbers.
HCF of 558, 639 is 9 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 558, 639 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 558, 639 is 9.
HCF(558, 639) = 9
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 558, 639 is 9.
Step 1: Since 639 > 558, we apply the division lemma to 639 and 558, to get
639 = 558 x 1 + 81
Step 2: Since the reminder 558 ≠ 0, we apply division lemma to 81 and 558, to get
558 = 81 x 6 + 72
Step 3: We consider the new divisor 81 and the new remainder 72, and apply the division lemma to get
81 = 72 x 1 + 9
We consider the new divisor 72 and the new remainder 9, and apply the division lemma to get
72 = 9 x 8 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 9, the HCF of 558 and 639 is 9
Notice that 9 = HCF(72,9) = HCF(81,72) = HCF(558,81) = HCF(639,558) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 558, 639?
Answer: HCF of 558, 639 is 9 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 558, 639 using Euclid's Algorithm?
Answer: For arbitrary numbers 558, 639 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.