Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 585, 178 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 585, 178 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 585, 178 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 585, 178 is 1.
HCF(585, 178) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 585, 178 is 1.
Step 1: Since 585 > 178, we apply the division lemma to 585 and 178, to get
585 = 178 x 3 + 51
Step 2: Since the reminder 178 ≠ 0, we apply division lemma to 51 and 178, to get
178 = 51 x 3 + 25
Step 3: We consider the new divisor 51 and the new remainder 25, and apply the division lemma to get
51 = 25 x 2 + 1
We consider the new divisor 25 and the new remainder 1, and apply the division lemma to get
25 = 1 x 25 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 585 and 178 is 1
Notice that 1 = HCF(25,1) = HCF(51,25) = HCF(178,51) = HCF(585,178) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 585, 178?
Answer: HCF of 585, 178 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 585, 178 using Euclid's Algorithm?
Answer: For arbitrary numbers 585, 178 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.