Highest Common Factor of 594, 3570 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 594, 3570 i.e. 6 the largest integer that leaves a remainder zero for all numbers.

HCF of 594, 3570 is 6 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 594, 3570 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 594, 3570 is 6.

HCF(594, 3570) = 6

HCF of 594, 3570 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 594, 3570 is 6.

Highest Common Factor of 594,3570 using Euclid's algorithm

Highest Common Factor of 594,3570 is 6

Step 1: Since 3570 > 594, we apply the division lemma to 3570 and 594, to get

3570 = 594 x 6 + 6

Step 2: Since the reminder 594 ≠ 0, we apply division lemma to 6 and 594, to get

594 = 6 x 99 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 6, the HCF of 594 and 3570 is 6

Notice that 6 = HCF(594,6) = HCF(3570,594) .

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Frequently Asked Questions on HCF of 594, 3570 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 594, 3570?

Answer: HCF of 594, 3570 is 6 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 594, 3570 using Euclid's Algorithm?

Answer: For arbitrary numbers 594, 3570 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.