Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 667, 127 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 667, 127 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 667, 127 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 667, 127 is 1.
HCF(667, 127) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 667, 127 is 1.
Step 1: Since 667 > 127, we apply the division lemma to 667 and 127, to get
667 = 127 x 5 + 32
Step 2: Since the reminder 127 ≠ 0, we apply division lemma to 32 and 127, to get
127 = 32 x 3 + 31
Step 3: We consider the new divisor 32 and the new remainder 31, and apply the division lemma to get
32 = 31 x 1 + 1
We consider the new divisor 31 and the new remainder 1, and apply the division lemma to get
31 = 1 x 31 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 667 and 127 is 1
Notice that 1 = HCF(31,1) = HCF(32,31) = HCF(127,32) = HCF(667,127) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 667, 127?
Answer: HCF of 667, 127 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 667, 127 using Euclid's Algorithm?
Answer: For arbitrary numbers 667, 127 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.