Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 682, 2858 i.e. 2 the largest integer that leaves a remainder zero for all numbers.
HCF of 682, 2858 is 2 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 682, 2858 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 682, 2858 is 2.
HCF(682, 2858) = 2
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 682, 2858 is 2.
Step 1: Since 2858 > 682, we apply the division lemma to 2858 and 682, to get
2858 = 682 x 4 + 130
Step 2: Since the reminder 682 ≠ 0, we apply division lemma to 130 and 682, to get
682 = 130 x 5 + 32
Step 3: We consider the new divisor 130 and the new remainder 32, and apply the division lemma to get
130 = 32 x 4 + 2
We consider the new divisor 32 and the new remainder 2, and apply the division lemma to get
32 = 2 x 16 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 2, the HCF of 682 and 2858 is 2
Notice that 2 = HCF(32,2) = HCF(130,32) = HCF(682,130) = HCF(2858,682) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 682, 2858?
Answer: HCF of 682, 2858 is 2 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 682, 2858 using Euclid's Algorithm?
Answer: For arbitrary numbers 682, 2858 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.