Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 689, 825 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 689, 825 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 689, 825 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 689, 825 is 1.
HCF(689, 825) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 689, 825 is 1.
Step 1: Since 825 > 689, we apply the division lemma to 825 and 689, to get
825 = 689 x 1 + 136
Step 2: Since the reminder 689 ≠ 0, we apply division lemma to 136 and 689, to get
689 = 136 x 5 + 9
Step 3: We consider the new divisor 136 and the new remainder 9, and apply the division lemma to get
136 = 9 x 15 + 1
We consider the new divisor 9 and the new remainder 1, and apply the division lemma to get
9 = 1 x 9 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 689 and 825 is 1
Notice that 1 = HCF(9,1) = HCF(136,9) = HCF(689,136) = HCF(825,689) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 689, 825?
Answer: HCF of 689, 825 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 689, 825 using Euclid's Algorithm?
Answer: For arbitrary numbers 689, 825 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.