Highest Common Factor of 712, 536 using Euclid's algorithm
Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 712, 536 i.e. 8 the largest integer that leaves a remainder zero for all numbers.
HCF of 712, 536 is 8 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 712, 536 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 712, 536 is 8.
HCF(712, 536) = 8
HCF of 712, 536 using Euclid's algorithm
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 712, 536 is 8.
Highest Common Factor of 712,536 is 8
Step 1: Since 712 > 536, we apply the division lemma to 712 and 536, to get
712 = 536 x 1 + 176
Step 2: Since the reminder 536 ≠ 0, we apply division lemma to 176 and 536, to get
536 = 176 x 3 + 8
Step 3: We consider the new divisor 176 and the new remainder 8, and apply the division lemma to get
176 = 8 x 22 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 8, the HCF of 712 and 536 is 8
Notice that 8 = HCF(176,8) = HCF(536,176) = HCF(712,536) .
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Frequently Asked Questions on HCF of 712, 536 using Euclid's Algorithm
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 712, 536?
Answer: HCF of 712, 536 is 8 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 712, 536 using Euclid's Algorithm?
Answer: For arbitrary numbers 712, 536 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.
