Highest Common Factor of 735, 435, 247 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 735, 435, 247 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 735, 435, 247 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 735, 435, 247 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 735, 435, 247 is 1.

HCF(735, 435, 247) = 1

HCF of 735, 435, 247 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 735, 435, 247 is 1.

Highest Common Factor of 735,435,247 using Euclid's algorithm

Highest Common Factor of 735,435,247 is 1

Step 1: Since 735 > 435, we apply the division lemma to 735 and 435, to get

735 = 435 x 1 + 300

Step 2: Since the reminder 435 ≠ 0, we apply division lemma to 300 and 435, to get

435 = 300 x 1 + 135

Step 3: We consider the new divisor 300 and the new remainder 135, and apply the division lemma to get

300 = 135 x 2 + 30

We consider the new divisor 135 and the new remainder 30,and apply the division lemma to get

135 = 30 x 4 + 15

We consider the new divisor 30 and the new remainder 15,and apply the division lemma to get

30 = 15 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 15, the HCF of 735 and 435 is 15

Notice that 15 = HCF(30,15) = HCF(135,30) = HCF(300,135) = HCF(435,300) = HCF(735,435) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 247 > 15, we apply the division lemma to 247 and 15, to get

247 = 15 x 16 + 7

Step 2: Since the reminder 15 ≠ 0, we apply division lemma to 7 and 15, to get

15 = 7 x 2 + 1

Step 3: We consider the new divisor 7 and the new remainder 1, and apply the division lemma to get

7 = 1 x 7 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 15 and 247 is 1

Notice that 1 = HCF(7,1) = HCF(15,7) = HCF(247,15) .

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Frequently Asked Questions on HCF of 735, 435, 247 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 735, 435, 247?

Answer: HCF of 735, 435, 247 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 735, 435, 247 using Euclid's Algorithm?

Answer: For arbitrary numbers 735, 435, 247 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.