Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 793, 708 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 793, 708 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 793, 708 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 793, 708 is 1.
HCF(793, 708) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 793, 708 is 1.
Step 1: Since 793 > 708, we apply the division lemma to 793 and 708, to get
793 = 708 x 1 + 85
Step 2: Since the reminder 708 ≠ 0, we apply division lemma to 85 and 708, to get
708 = 85 x 8 + 28
Step 3: We consider the new divisor 85 and the new remainder 28, and apply the division lemma to get
85 = 28 x 3 + 1
We consider the new divisor 28 and the new remainder 1, and apply the division lemma to get
28 = 1 x 28 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 793 and 708 is 1
Notice that 1 = HCF(28,1) = HCF(85,28) = HCF(708,85) = HCF(793,708) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 793, 708?
Answer: HCF of 793, 708 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 793, 708 using Euclid's Algorithm?
Answer: For arbitrary numbers 793, 708 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.