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Highest Common Factor of 867, 255 using Euclid's algorithm

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 867, 255 i.e. 51 the largest integer that leaves a remainder zero for all numbers.

HCF of 867, 255 is 51 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 867, 255 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 867, 255 is 51.

HCF(867, 255) = 51

HCF of 867, 255 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 867, 255 is 51.

Highest Common Factor of 867,255 using Euclid's algorithm

Step 1: Since 867 > 255, we apply the division lemma to 867 and 255, to get

867 = 255 x 3 + 102

Step 2: Since the reminder 255 ≠ 0, we apply division lemma to 102 and 255, to get

255 = 102 x 2 + 51

Step 3: We consider the new divisor 102 and the new remainder 51, and apply the division lemma to get

102 = 51 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 51, the HCF of 867 and 255 is 51

Notice that 51 = HCF(102,51) = HCF(255,102) = HCF(867,255) .

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Frequently Asked Questions on HCF of 867, 255 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 867, 255?

Answer: HCF of 867, 255 is 51 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 867, 255 using Euclid's Algorithm?

Answer: For arbitrary numbers 867, 255 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.