Highest Common Factor of 8725, 3258, 12758 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023

HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 8725, 3258, 12758 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 8725, 3258, 12758 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 8725, 3258, 12758 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 8725, 3258, 12758 is 1.

HCF(8725, 3258, 12758) = 1

HCF of 8725, 3258, 12758 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 8725, 3258, 12758 is 1.

Highest Common Factor of 8725,3258,12758 using Euclid's algorithm

Highest Common Factor of 8725,3258,12758 is 1

Step 1: Since 8725 > 3258, we apply the division lemma to 8725 and 3258, to get

8725 = 3258 x 2 + 2209

Step 2: Since the reminder 3258 ≠ 0, we apply division lemma to 2209 and 3258, to get

3258 = 2209 x 1 + 1049

Step 3: We consider the new divisor 2209 and the new remainder 1049, and apply the division lemma to get

2209 = 1049 x 2 + 111

We consider the new divisor 1049 and the new remainder 111,and apply the division lemma to get

1049 = 111 x 9 + 50

We consider the new divisor 111 and the new remainder 50,and apply the division lemma to get

111 = 50 x 2 + 11

We consider the new divisor 50 and the new remainder 11,and apply the division lemma to get

50 = 11 x 4 + 6

We consider the new divisor 11 and the new remainder 6,and apply the division lemma to get

11 = 6 x 1 + 5

We consider the new divisor 6 and the new remainder 5,and apply the division lemma to get

6 = 5 x 1 + 1

We consider the new divisor 5 and the new remainder 1,and apply the division lemma to get

5 = 1 x 5 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 8725 and 3258 is 1

Notice that 1 = HCF(5,1) = HCF(6,5) = HCF(11,6) = HCF(50,11) = HCF(111,50) = HCF(1049,111) = HCF(2209,1049) = HCF(3258,2209) = HCF(8725,3258) .

We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 12758 > 1, we apply the division lemma to 12758 and 1, to get

12758 = 1 x 12758 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 12758 is 1

Notice that 1 = HCF(12758,1) .

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Frequently Asked Questions on HCF of 8725, 3258, 12758 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 8725, 3258, 12758?

Answer: HCF of 8725, 3258, 12758 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 8725, 3258, 12758 using Euclid's Algorithm?

Answer: For arbitrary numbers 8725, 3258, 12758 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.