Evaluate 4^3-(3+4)^2

$4^{3} - {(3 + 4)}^{2}$

Step 1

Simplify each term.

Raise $4$ to the power of $3$ .

$64 - {(3 + 4)}^{2}$

Add $3$ and $4$ .

$64 - 7^{2}$

Raise $7$ to the power of $2$ .

$64 - 1 \cdot 49$

Multiply $- 1$ by $49$ .

$64 - 49$

$64 - 49$

Step 2

Subtract $49$ from $64$ .

$15$

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