Evaluate Using the Given Value y-(4-x-y÷2) ; use x=3 ; and y=2

$y - (4 - x - y \div 2)$ ; use $x = 3$ ; and $y = 2$

Step 1

Replace the variable $x$ with $3$ in the expression.

$y - (4 - (3) - y \div 2)$

Step 2

Replace the variable $y$ with $2$ in the expression.

$(2) - (4 - (3) - 2 \div 2)$

Step 3

Simplify each term.

Find the common denominator.

Write $4$ as a fraction with denominator $1$ .

$2 - (\frac{4}{1} - (3) - 2 \div 2)$

Multiply $\frac{4}{1}$ by $\frac{2}{2}$ .

$2 - (\frac{4}{1} \cdot \frac{2}{2} - (3) - 2 \div 2)$

Multiply $\frac{4}{1}$ by $\frac{2}{2}$ .

$2 - (\frac{4 \cdot 2}{2} - (3) - 2 \div 2)$

Write $- (3)$ as a fraction with denominator $1$ .

$2 - (\frac{4 \cdot 2}{2} + \frac{- (3)}{1} - 2 \div 2)$

Multiply $\frac{- (3)}{1}$ by $\frac{2}{2}$ .

$2 - (\frac{4 \cdot 2}{2} + \frac{- (3)}{1} \cdot \frac{2}{2} - 2 \div 2)$

Multiply $\frac{- (3)}{1}$ by $\frac{2}{2}$ .

$2 - (\frac{4 \cdot 2}{2} + \frac{- (3) \cdot 2}{2} - 2 \div 2)$

Combine the numerators over the common denominator.

$2 - \frac{4 \cdot 2 - (3) \cdot 2 - 2}{2}$

Simplify each term.

Multiply $4$ by $2$ .

$2 - \frac{8 - (3) \cdot 2 - 2}{2}$

Multiply $- (3) \cdot 2$ .

Multiply $- 1$ by $3$ .

$2 - \frac{8 - 3 \cdot 2 - 2}{2}$

Multiply $- 3$ by $2$ .

$2 - \frac{8 - 6 - 2}{2}$

Subtract $6$ from $8$ .

$2 - \frac{2 - 2}{2}$

Subtract $2$ from $2$ .

$2 - \frac{0}{2}$

Divide $0$ by $2$ .

$2 - 0$

Multiply $- 1$ by $0$ .

$2 + 0$

Step 4

Add $2$ and $0$ .

$2$