Expand the Trigonometric Expression (4x+3y)^3

${(4 x + 3 y)}^{3}$

Use the Binomial Theorem.

${(4 x)}^{3} + 3 {(4 x)}^{2} (3 y) + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Simplify each term.

Apply the product rule to $4 x$ .

$4^{3} x^{3} + 3 {(4 x)}^{2} (3 y) + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Raise $4$ to the power of $3$ .

$64 x^{3} + 3 {(4 x)}^{2} (3 y) + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Rewrite using the commutative property of multiplication.

$64 x^{3} + 3 \cdot 3 {(4 x)}^{2} y + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Multiply $3$ by $3$ .

$64 x^{3} + 9 {(4 x)}^{2} y + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Apply the product rule to $4 x$ .

$64 x^{3} + 9 (4^{2} x^{2}) y + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Raise $4$ to the power of $2$ .

$64 x^{3} + 9 (16 x^{2}) y + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Multiply $16$ by $9$ .

$64 x^{3} + 144 x^{2} y + 3 (4 x) {(3 y)}^{2} + {(3 y)}^{3}$

Multiply $4$ by $3$ .

$64 x^{3} + 144 x^{2} y + 12 x {(3 y)}^{2} + {(3 y)}^{3}$

Apply the product rule to $3 y$ .

$64 x^{3} + 144 x^{2} y + 12 x (3^{2} y^{2}) + {(3 y)}^{3}$

Rewrite using the commutative property of multiplication.

$64 x^{3} + 144 x^{2} y + 12 \cdot 3^{2} x y^{2} + {(3 y)}^{3}$

Raise $3$ to the power of $2$ .

$64 x^{3} + 144 x^{2} y + 12 \cdot 9 x y^{2} + {(3 y)}^{3}$

Multiply $12$ by $9$ .

$64 x^{3} + 144 x^{2} y + 108 x y^{2} + {(3 y)}^{3}$

Apply the product rule to $3 y$ .

$64 x^{3} + 144 x^{2} y + 108 x y^{2} + 3^{3} y^{3}$

Raise $3$ to the power of $3$ .

$64 x^{3} + 144 x^{2} y + 108 x y^{2} + 27 y^{3}$