Find the Discriminant 7x^2-4x+1=0

$7 x^{2} - 4 x + 1 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 4)}^{2} - 4 (7 \cdot 1)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$16 - 4 (7 \cdot 1)$

Multiply $- 4 (7 \cdot 1)$ .

Multiply $7$ by $1$ .

$16 - 4 \cdot 7$

Multiply $- 4$ by $7$ .

$16 - 28$

Subtract $28$ from $16$ .

$- 12$