Find the Domain y = log base 3 of x+5

$y = \log_{3} (x + 5)$

Set the argument in $\log_{3} (x + 5)$ greater than $0$ to find where the expression is defined.

$x + 5 > 0$

Subtract $5$ from both sides of the inequality.

$x > - 5$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- 5, \infty)$

Set-Builder Notation:

${x | x > - 5}$