Find the Midpoint (9,8) , (-3,-16)

$(9, 8)$ , $(- 3, - 16)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{9 - 3}{2}, \frac{8 - 16}{2})$

Subtract $3$ from $9$ .

$(\frac{6}{2}, \frac{8 - 16}{2})$

Divide $6$ by $2$ .

$(3, \frac{8 - 16}{2})$

Cancel the common factor of $8 - 16$ and $2$ .

Factor $2$ out of $8$ .

$(3, \frac{2 \cdot 4 - 16}{2})$

Factor $2$ out of $- 16$ .

$(3, \frac{2 \cdot 4 + 2 \cdot - 8}{2})$

Factor $2$ out of $2 \cdot 4 + 2 \cdot - 8$ .

$(3, \frac{2 \cdot (4 - 8)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(3, \frac{2 \cdot (4 - 8)}{2 (1)})$

Cancel the common factor.

$(3, \frac{2 \cdot (4 - 8)}{2 \cdot 1})$

Rewrite the expression.

$(3, \frac{4 - 8}{1})$

Divide $4 - 8$ by $1$ .

$(3, 4 - 8)$

Subtract $8$ from $4$ .

$(3, - 4)$