Find the Slope -3x-y=-3

$- 3 x - y = - 3$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Add $3 x$ to both sides of the equation.

$- y = - 3 + 3 x$

Divide each term in $- y = - 3 + 3 x$ by $- 1$ and simplify.

Divide each term in $- y = - 3 + 3 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 3}{- 1} + \frac{3 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 3}{- 1} + \frac{3 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 3}{- 1} + \frac{3 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 3$ by $- 1$ .

$y = 3 + \frac{3 x}{- 1}$

Move the negative one from the denominator of $\frac{3 x}{- 1}$ .

$y = 3 - 1 \cdot (3 x)$

Rewrite $- 1 \cdot (3 x)$ as $- (3 x)$ .

$y = 3 - (3 x)$

Multiply $3$ by $- 1$ .

$y = 3 - 3 x$

Reorder $3$ and $- 3 x$ .

$y = - 3 x + 3$

Step 2

Using the slope-intercept form, the slope is $- 3$ .

$m = - 3$

Step 3