Find the x and y Intercepts f(x)=-2x^5-3x^2+2x-3x^4-6x^3

$f (x) = - 2 x^{5} - 3 x^{2} + 2 x - 3 x^{4} - 6 x^{3}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - 2 x^{5} - 3 x^{2} + 2 x - 3 x^{4} - 6 x^{3}$

Solve the equation.

Rewrite the equation as $- 2 x^{5} - 3 x^{2} + 2 x - 3 x^{4} - 6 x^{3} = 0$ .

$- 2 x^{5} - 3 x^{2} + 2 x - 3 x^{4} - 6 x^{3} = 0$

Reorder the polynomial.

$- 2 x^{5} - 3 x^{4} - 6 x^{3} - 3 x^{2} + 2 x$

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 0$

$q = \pm 1, \pm 2$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$0$

Substitute the possible roots one by one into the polynomial to find the actual roots. Simplify to check if the value is $0$ , which means it is a root.

$- 2 {(0)}^{5} - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Simplify the expression. In this case, the expression is equal to $0$ so $x = 0$ is a root of the polynomial.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$- 2 \cdot 0 - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Multiply $- 2$ by $0$ .

$0 - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Raising $0$ to any positive power yields $0$ .

$0 - 3 \cdot 0 + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Multiply $- 3$ by $0$ .

$0 + 0 + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Multiply $2$ by $0$ .

$0 + 0 + 0 - 3 {(0)}^{4} - 6 {(0)}^{3}$

Raising $0$ to any positive power yields $0$ .

$0 + 0 + 0 - 3 \cdot 0 - 6 {(0)}^{3}$

Multiply $- 3$ by $0$ .

$0 + 0 + 0 + 0 - 6 {(0)}^{3}$

Raising $0$ to any positive power yields $0$ .

$0 + 0 + 0 + 0 - 6 \cdot 0$

Multiply $- 6$ by $0$ .

$0 + 0 + 0 + 0 + 0$

Simplify by adding numbers.

Add $0$ and $0$ .

$0 + 0 + 0 + 0$

Add $0$ and $0$ .

$0 + 0 + 0$

Add $0$ and $0$ .

$0 + 0$

Add $0$ and $0$ .

$0$

Since $0$ is a known root, divide the polynomial by $x + 0$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{- 2 x^{5} - 3 x^{2} + 2 x - 3 x^{4} - 6 x^{3}}{x + 0}$

Next, find the roots of the remaining polynomial. The order of the polynomial has been reduced by $1$ .

Place the numbers representing the divisor and the dividend into a division-like configuration.

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0					\xa0

The first number in the dividend $(- 2)$ is put into the first position of the result area (below the horizontal line).

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0					\xa0
	$- 2$

Multiply the newest entry in the result $(- 2)$ by the divisor $(0)$ and place the result of $(0)$ under the next term in the dividend $(- 3)$ .

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$				\xa0
	$- 2$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$				\xa0
	$- 2$	$- 3$

Multiply the newest entry in the result $(- 3)$ by the divisor $(0)$ and place the result of $(0)$ under the next term in the dividend $(- 6)$ .

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$			\xa0
	$- 2$	$- 3$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$			\xa0
	$- 2$	$- 3$	$- 6$

Multiply the newest entry in the result $(- 6)$ by the divisor $(0)$ and place the result of $(0)$ under the next term in the dividend $(- 3)$ .

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$	$0$		\xa0
	$- 2$	$- 3$	$- 6$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$	$0$		\xa0
	$- 2$	$- 3$	$- 6$	$- 3$

Multiply the newest entry in the result $(- 3)$ by the divisor $(0)$ and place the result of $(0)$ under the next term in the dividend $(2)$ .

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$	$0$	$0$	\xa0
	$- 2$	$- 3$	$- 6$	$- 3$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$	$0$	$0$	\xa0
	$- 2$	$- 3$	$- 6$	$- 3$	$2$

Multiply the newest entry in the result $(2)$ by the divisor $(0)$ and place the result of $(0)$ under the next term in the dividend $(0)$ .

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$	$0$	$0$	$0$
	$- 2$	$- 3$	$- 6$	$- 3$	$2$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$0$	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$
	\xa0	$0$	$0$	$0$	$0$	$0$
	$- 2$	$- 3$	$- 6$	$- 3$	$2$	$0$

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$- 2 x^{4} + - 3 x^{3} - 6 x^{2} + - 3 x + 2$

Simplify the quotient polynomial.

$- 2 x^{4} - 3 x^{3} - 6 x^{2} - 3 x + 2$

Solve the equation to find any remaining roots.

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 2$

$q = \pm 1, \pm 2$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm \frac{1}{2}, \pm 2$

Substitute the possible roots one by one into the polynomial to find the actual roots. Simplify to check if the value is $0$ , which means it is a root.

$- 2 {(- 1)}^{4} - 3 {(- 1)}^{3} - 6 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Simplify the expression. In this case, the expression is equal to $0$ so $x = - 1$ is a root of the polynomial.

Simplify each term.

Raise $- 1$ to the power of $4$ .

$- 2 \cdot 1 - 3 {(- 1)}^{3} - 6 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Multiply $- 2$ by $1$ .

$- 2 - 3 {(- 1)}^{3} - 6 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Raise $- 1$ to the power of $3$ .

$- 2 - 3 \cdot - 1 - 6 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Multiply $- 3$ by $- 1$ .

$- 2 + 3 - 6 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Raise $- 1$ to the power of $2$ .

$- 2 + 3 - 6 \cdot 1 - 3 \cdot - 1 + 2$

Multiply $- 6$ by $1$ .

$- 2 + 3 - 6 - 3 \cdot - 1 + 2$

Multiply $- 3$ by $- 1$ .

$- 2 + 3 - 6 + 3 + 2$

Simplify by adding and subtracting.

Add $- 2$ and $3$ .

$1 - 6 + 3 + 2$

Subtract $6$ from $1$ .

$- 5 + 3 + 2$

Add $- 5$ and $3$ .

$- 2 + 2$

Add $- 2$ and $2$ .

$0$

Since $- 1$ is a known root, divide the polynomial by $x + 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{- 2 x^{4} - 3 x^{3} - 6 x^{2} - 3 x + 2}{x + 1}$

Next, find the roots of the remaining polynomial. The order of the polynomial has been reduced by $1$ .

Place the numbers representing the divisor and the dividend into a division-like configuration.

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0				\xa0

The first number in the dividend $(- 2)$ is put into the first position of the result area (below the horizontal line).

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0				\xa0
	$- 2$

Multiply the newest entry in the result $(- 2)$ by the divisor $(- 1)$ and place the result of $(2)$ under the next term in the dividend $(- 3)$ .

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$			\xa0
	$- 2$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$			\xa0
	$- 2$	$- 1$

Multiply the newest entry in the result $(- 1)$ by the divisor $(- 1)$ and place the result of $(1)$ under the next term in the dividend $(- 6)$ .

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$	$1$		\xa0
	$- 2$	$- 1$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$	$1$		\xa0
	$- 2$	$- 1$	$- 5$

Multiply the newest entry in the result $(- 5)$ by the divisor $(- 1)$ and place the result of $(5)$ under the next term in the dividend $(- 3)$ .

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$	$1$	$5$	\xa0
	$- 2$	$- 1$	$- 5$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$	$1$	$5$	\xa0
	$- 2$	$- 1$	$- 5$	$2$

Multiply the newest entry in the result $(2)$ by the divisor $(- 1)$ and place the result of $(- 2)$ under the next term in the dividend $(2)$ .

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$	$1$	$5$	$- 2$
	$- 2$	$- 1$	$- 5$	$2$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$- 2$	$- 3$	$- 6$	$- 3$	$2$
	\xa0	$2$	$1$	$5$	$- 2$
	$- 2$	$- 1$	$- 5$	$2$	$0$

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$- 2 x^{3} + - 1 x^{2} + (- 5) x + 2$

Simplify the quotient polynomial.

$- 2 x^{3} - x^{2} - 5 x + 2$

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx 0.35646772$

The polynomial can be written as a set of linear factors.

$(x + 1) (x - 0.35646772)$

These are the roots (zeros) of the polynomial $- 2 x^{4} - 3 x^{3} - 6 x^{2} - 3 x + 2$ .

$x = - 1, 0.35646772$

The polynomial can be written as a set of linear factors.

$(x + 0) (x + 1) (x - 0.35646772)$

These are the roots (zeros) of the polynomial $- 2 x^{5} - 3 x^{4} - 6 x^{3} - 3 x^{2} + 2 x$ .

$x = 0, - 1, 0.35646772$

x-intercept(s) in point form.

x-intercept(s): $(0, 0), (- 1, 0), (0.35646772, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - 2 {(0)}^{5} - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Solve the equation.

Remove parentheses.

$y = - 2 \cdot 0^{5} - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Remove parentheses.

$y = - 2 \cdot 0^{5} - 3 \cdot 0^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Remove parentheses.

$y = - 2 \cdot 0^{5} - 3 \cdot 0^{2} + 2 (0) - 3 \cdot 0^{4} - 6 {(0)}^{3}$

Remove parentheses.

$y = - 2 \cdot 0^{5} - 3 \cdot 0^{2} + 2 (0) - 3 \cdot 0^{4} - 6 \cdot 0^{3}$

Remove parentheses.

$y = - 2 {(0)}^{5} - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Simplify $- 2 {(0)}^{5} - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = - 2 \cdot 0 - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Multiply $- 2$ by $0$ .

$y = 0 - 3 {(0)}^{2} + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Raising $0$ to any positive power yields $0$ .

$y = 0 - 3 \cdot 0 + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Multiply $- 3$ by $0$ .

$y = 0 + 0 + 2 (0) - 3 {(0)}^{4} - 6 {(0)}^{3}$

Multiply $2$ by $0$ .

$y = 0 + 0 + 0 - 3 {(0)}^{4} - 6 {(0)}^{3}$

Raising $0$ to any positive power yields $0$ .

$y = 0 + 0 + 0 - 3 \cdot 0 - 6 {(0)}^{3}$

Multiply $- 3$ by $0$ .

$y = 0 + 0 + 0 + 0 - 6 {(0)}^{3}$

Raising $0$ to any positive power yields $0$ .

$y = 0 + 0 + 0 + 0 - 6 \cdot 0$

Multiply $- 6$ by $0$ .

$y = 0 + 0 + 0 + 0 + 0$

Simplify by adding numbers.

Add $0$ and $0$ .

$y = 0 + 0 + 0 + 0$

Add $0$ and $0$ .

$y = 0 + 0 + 0$

Add $0$ and $0$ .

$y = 0 + 0$

Add $0$ and $0$ .

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

List the intersections.

x-intercept(s): $(0, 0), (- 1, 0), (0.35646772, 0)$

y-intercept(s): $(0, 0)$

Find the x and y Intercepts f(x)=-2x^5-3x^2+2x-3x^4-6x^3

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