Solve for a 6>=-6(a+2)

$6 \geq - 6 (a + 2)$

Step 1

Rewrite so $a$ is on the left side of the inequality.

$- 6 (a + 2) \leq 6$

Step 2

Divide each term in $- 6 (a + 2) \leq 6$ by $- 6$ and simplify.

Divide each term in $- 6 (a + 2) \leq 6$ by $- 6$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 6 (a + 2)}{- 6} \geq \frac{6}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 (a + 2)}{- 6} \geq \frac{6}{- 6}$

Divide $a + 2$ by $1$ .

$a + 2 \geq \frac{6}{- 6}$

Simplify the right side.

Divide $6$ by $- 6$ .

$a + 2 \geq - 1$

Step 3

Move all terms not containing $a$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$a \geq - 1 - 2$

Subtract $2$ from $- 1$ .

$a \geq - 3$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$a \geq - 3$

Interval Notation:

$[- 3, \infty)$

Solve for a 6>=-6(a+2)

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