Solve for b 1/2(b+2)+3b=-1

$\frac{1}{2} (b + 2) + 3 b = - 1$

Simplify $\frac{1}{2} \cdot (b + 2) + 3 b$ .

Simplify each term.

Apply the distributive property.

$\frac{1}{2} b + \frac{1}{2} \cdot 2 + 3 b = - 1$

Combine $\frac{1}{2}$ and $b$ .

$\frac{b}{2} + \frac{1}{2} \cdot 2 + 3 b = - 1$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{b}{2} + \frac{1}{2} \cdot 2 + 3 b = - 1$

Rewrite the expression.

$\frac{b}{2} + 1 + 3 b = - 1$

To write $3 b$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{b}{2} + 3 b \cdot \frac{2}{2} + 1 = - 1$

Simplify terms.

Combine $3 b$ and $\frac{2}{2}$ .

$\frac{b}{2} + \frac{3 b \cdot 2}{2} + 1 = - 1$

Combine the numerators over the common denominator.

$\frac{b + 3 b \cdot 2}{2} + 1 = - 1$

Simplify each term.

Simplify the numerator.

Factor $b$ out of $b + 3 b \cdot 2$ .

Raise $b$ to the power of $1$ .

$\frac{b^{1} + 3 b \cdot 2}{2} + 1 = - 1$

Factor $b$ out of $b^{1}$ .

$\frac{b \cdot 1 + 3 b \cdot 2}{2} + 1 = - 1$

Factor $b$ out of $3 b \cdot 2$ .

$\frac{b \cdot 1 + b (3 \cdot 2)}{2} + 1 = - 1$

Factor $b$ out of $b \cdot 1 + b (3 \cdot 2)$ .

$\frac{b (1 + 3 \cdot 2)}{2} + 1 = - 1$

Multiply $3$ by $2$ .

$\frac{b (1 + 6)}{2} + 1 = - 1$

Add $1$ and $6$ .

$\frac{b \cdot 7}{2} + 1 = - 1$

Move $7$ to the left of $b$ .

$\frac{7 b}{2} + 1 = - 1$

Move all terms not containing $b$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$\frac{7 b}{2} = - 1 - 1$

Subtract $1$ from $- 1$ .

$\frac{7 b}{2} = - 2$

Multiply both sides of the equation by $\frac{2}{7}$ .

$\frac{2}{7} \cdot \frac{7 b}{2} = \frac{2}{7} \cdot - 2$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{2}{7} \cdot \frac{7 b}{2}$ .

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2}{7} \cdot \frac{7 b}{2} = \frac{2}{7} \cdot - 2$

Rewrite the expression.

$\frac{1}{7} (7 b) = \frac{2}{7} \cdot - 2$

Cancel the common factor of $7$ .

Factor $7$ out of $7 b$ .

$\frac{1}{7} (7 (b)) = \frac{2}{7} \cdot - 2$

Cancel the common factor.

$\frac{1}{7} (7 b) = \frac{2}{7} \cdot - 2$

Rewrite the expression.

$b = \frac{2}{7} \cdot - 2$

Simplify the right side.

Simplify $\frac{2}{7} \cdot - 2$ .

Multiply $\frac{2}{7} \cdot - 2$ .

Combine $\frac{2}{7}$ and $- 2$ .

$b = \frac{2 \cdot - 2}{7}$

Multiply $2$ by $- 2$ .

$b = \frac{- 4}{7}$

Move the negative in front of the fraction.

$b = - \frac{4}{7}$

The result can be shown in multiple forms.

Exact Form:

$b = - \frac{4}{7}$

Decimal Form:

$b = - 0.\overline{571428}$

Solve for b 1/2(b+2)+3b=-1

Related Questions

Support LCMGCF.com by disabling your adblocker.