Solve for c 65=5+3/4c

$65 = 5 + \frac{3}{4} c$

Step 1

Rewrite the equation as $5 + \frac{3}{4} c = 65$ .

$5 + \frac{3}{4} c = 65$

Step 2

Combine $\frac{3}{4}$ and $c$ .

$5 + \frac{3 c}{4} = 65$

Step 3

Move all terms not containing $c$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$\frac{3 c}{4} = 65 - 5$

Subtract $5$ from $65$ .

$\frac{3 c}{4} = 60$

Step 4

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} \cdot \frac{3 c}{4} = \frac{4}{3} \cdot 60$

Step 5

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} \cdot \frac{3 c}{4}$ .

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4}{3} \cdot \frac{3 c}{4} = \frac{4}{3} \cdot 60$

Rewrite the expression.

$\frac{1}{3} (3 c) = \frac{4}{3} \cdot 60$

Cancel the common factor of $3$ .

Factor $3$ out of $3 c$ .

$\frac{1}{3} (3 (c)) = \frac{4}{3} \cdot 60$

Cancel the common factor.

$\frac{1}{3} (3 c) = \frac{4}{3} \cdot 60$

Rewrite the expression.

$c = \frac{4}{3} \cdot 60$

Simplify the right side.

Simplify $\frac{4}{3} \cdot 60$ .

Cancel the common factor of $3$ .

Factor $3$ out of $60$ .

$c = \frac{4}{3} \cdot (3 (20))$

Cancel the common factor.

$c = \frac{4}{3} \cdot (3 \cdot 20)$

Rewrite the expression.

$c = 4 \cdot 20$

Multiply $4$ by $20$ .

$c = 80$