Solve for c c = square root of 3^2+4^2

$c = \sqrt{3^{2} + 4^{2}}$

Raise $3$ to the power of $2$ .

$c = \sqrt{9 + 4^{2}}$

Raise $4$ to the power of $2$ .

$c = \sqrt{9 + 16}$

Add $9$ and $16$ .

$c = \sqrt{25}$

Rewrite $25$ as $5^{2}$ .

$c = \sqrt{5^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$c = 5$