Solve for n 411/3+388=n-79

$\frac{411}{3} + 388 = n - 79$

Rewrite the equation as $n - 79 = \frac{411}{3} + 388$ .

$n - 79 = \frac{411}{3} + 388$

Simplify $\frac{411}{3} + 388$ .

Divide $411$ by $3$ .

$n - 79 = 137 + 388$

Add $137$ and $388$ .

$n - 79 = 525$

Move all terms not containing $n$ to the right side of the equation.

Add $79$ to both sides of the equation.

$n = 525 + 79$

Add $525$ and $79$ .

$n = 604$