Solve for q -6q+1>=2q-10

$- 6 q + 1 \geq 2 q - 10$

Step 1

Move all terms containing $q$ to the left side of the inequality.

Subtract $2 q$ from both sides of the inequality.

$- 6 q + 1 - 2 q \geq - 10$

Subtract $2 q$ from $- 6 q$ .

$- 8 q + 1 \geq - 10$

Step 2

Move all terms not containing $q$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$- 8 q \geq - 10 - 1$

Subtract $1$ from $- 10$ .

$- 8 q \geq - 11$

Step 3

Divide each term in $- 8 q \geq - 11$ by $- 8$ and simplify.

Divide each term in $- 8 q \geq - 11$ by $- 8$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 8 q}{- 8} \leq \frac{- 11}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 q}{- 8} \leq \frac{- 11}{- 8}$

Divide $q$ by $1$ .

$q \leq \frac{- 11}{- 8}$

Simplify the right side.

Dividing two negative values results in a positive value.

$q \leq \frac{11}{8}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$q \leq \frac{11}{8}$

Interval Notation:

$(- \infty, \frac{11}{8}]$

Solve for q -6q+1>=2q-10

Related Questions

Support LCMGCF.com by disabling your adblocker.