Solve for r 6r=3(4-2r)

$6 r = 3 (4 - 2 r)$

Step 1

Simplify $3 (4 - 2 r)$ .

Apply the distributive property.

$6 r = 3 \cdot 4 + 3 (- 2 r)$

Multiply.

Multiply $3$ by $4$ .

$6 r = 12 + 3 (- 2 r)$

Multiply $- 2$ by $3$ .

$6 r = 12 - 6 r$

Step 2

Move all terms containing $r$ to the left side of the equation.

Add $6 r$ to both sides of the equation.

$6 r + 6 r = 12$

Add $6 r$ and $6 r$ .

$12 r = 12$

Step 3

Divide each term in $12 r = 12$ by $12$ and simplify.

Divide each term in $12 r = 12$ by $12$ .

$\frac{12 r}{12} = \frac{12}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 r}{12} = \frac{12}{12}$

Divide $r$ by $1$ .

$r = \frac{12}{12}$

Simplify the right side.

Divide $12$ by $12$ .

$r = 1$