Solve for x 0=(3(2x-1))/(2x-3)

$0 = \frac{3 (2 x - 1)}{2 x - 3}$

Set the numerator equal to zero.

$3 (2 x - 1) = 0$

Solve the equation for $x$ .

Divide each term in $3 (2 x - 1) = 0$ by $3$ and simplify.

Divide each term in $3 (2 x - 1) = 0$ by $3$ .

$\frac{3 (2 x - 1)}{3} = \frac{0}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (2 x - 1)}{3} = \frac{0}{3}$

Divide $2 x - 1$ by $1$ .

$2 x - 1 = \frac{0}{3}$

Simplify the right side.

Divide $0$ by $3$ .

$2 x - 1 = 0$

Add $1$ to both sides of the equation.

$2 x = 1$

Divide each term in $2 x = 1$ by $2$ and simplify.

Divide each term in $2 x = 1$ by $2$ .

$\frac{2 x}{2} = \frac{1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{1}{2}$

Divide $x$ by $1$ .

$x = \frac{1}{2}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{2}$

Decimal Form:

$x = 0.5$