Solve for x 1/3(24x-54)=11(x-4)+5

$\frac{1}{3} (24 x - 54) = 11 (x - 4) + 5$

Simplify $\frac{1}{3} \cdot (24 x - 54)$ .

Rewrite.

$0 + 0 + \frac{1}{3} \cdot (24 x - 54) = 11 (x - 4) + 5$

Simplify by adding zeros.

$\frac{1}{3} \cdot (24 x - 54) = 11 (x - 4) + 5$

Apply the distributive property.

$\frac{1}{3} (24 x) + \frac{1}{3} \cdot - 54 = 11 (x - 4) + 5$

Cancel the common factor of $3$ .

Factor $3$ out of $24 x$ .

$\frac{1}{3} (3 (8 x)) + \frac{1}{3} \cdot - 54 = 11 (x - 4) + 5$

Cancel the common factor.

$\frac{1}{3} (3 (8 x)) + \frac{1}{3} \cdot - 54 = 11 (x - 4) + 5$

Rewrite the expression.

$8 x + \frac{1}{3} \cdot - 54 = 11 (x - 4) + 5$

Cancel the common factor of $3$ .

Factor $3$ out of $- 54$ .

$8 x + \frac{1}{3} \cdot (3 (- 18)) = 11 (x - 4) + 5$

Cancel the common factor.

$8 x + \frac{1}{3} \cdot (3 \cdot - 18) = 11 (x - 4) + 5$

Rewrite the expression.

$8 x - 18 = 11 (x - 4) + 5$

Simplify $11 (x - 4) + 5$ .

Simplify each term.

Apply the distributive property.

$8 x - 18 = 11 x + 11 \cdot - 4 + 5$

Multiply $11$ by $- 4$ .

$8 x - 18 = 11 x - 44 + 5$

Add $- 44$ and $5$ .

$8 x - 18 = 11 x - 39$

Move all terms containing $x$ to the left side of the equation.

Subtract $11 x$ from both sides of the equation.

$8 x - 18 - 11 x = - 39$

Subtract $11 x$ from $8 x$ .

$- 3 x - 18 = - 39$

Move all terms not containing $x$ to the right side of the equation.

Add $18$ to both sides of the equation.

$- 3 x = - 39 + 18$

Add $- 39$ and $18$ .

$- 3 x = - 21$

Divide each term in $- 3 x = - 21$ by $- 3$ and simplify.

Divide each term in $- 3 x = - 21$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{- 21}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{- 21}{- 3}$

Divide $x$ by $1$ .

$x = \frac{- 21}{- 3}$

Simplify the right side.

Divide $- 21$ by $- 3$ .

$x = 7$

Solve for x 1/3(24x-54)=11(x-4)+5

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