Solve for x 27^(3x)=9^(x+1)

$27^{3 x} = 9^{x + 1}$

Step 1

Create equivalent expressions in the equation that all have equal bases.

$3^{3 (3 x)} = 3^{2 (x + 1)}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$3 (3 x) = 2 (x + 1)$

Step 3

Solve for $x$ .

Multiply $3$ by $3$ .

$9 x = 2 (x + 1)$

Simplify $2 (x + 1)$ .

Apply the distributive property.

$9 x = 2 x + 2 \cdot 1$

Multiply $2$ by $1$ .

$9 x = 2 x + 2$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$9 x - 2 x = 2$

Subtract $2 x$ from $9 x$ .

$7 x = 2$

Divide each term in $7 x = 2$ by $7$ and simplify.

Divide each term in $7 x = 2$ by $7$ .

$\frac{7 x}{7} = \frac{2}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{2}{7}$

Divide $x$ by $1$ .

$x = \frac{2}{7}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{2}{7}$

Decimal Form:

$x = 0.\overline{285714}$