Solve for x 8x-7<25<2x+9

$8 x - 7 < 25 < 2 x + 9$

Solve $8 x - 7 < 25$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Add $7$ to both sides of the inequality.

$8 x < 25 + 7$

Add $25$ and $7$ .

$8 x < 32$

Divide each term in $8 x < 32$ by $8$ and simplify.

Divide each term in $8 x < 32$ by $8$ .

$\frac{8 x}{8} < \frac{32}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} < \frac{32}{8}$

Divide $x$ by $1$ .

$x < \frac{32}{8}$

Simplify the right side.

Divide $32$ by $8$ .

$x < 4$

Solve $25 < 2 x + 9$ for $x$ .

Rewrite so $x$ is on the left side of the inequality.

$2 x + 9 > 25$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $9$ from both sides of the inequality.

$2 x > 25 - 9$

Subtract $9$ from $25$ .

$2 x > 16$

Divide each term in $2 x > 16$ by $2$ and simplify.

Divide each term in $2 x > 16$ by $2$ .

$\frac{2 x}{2} > \frac{16}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} > \frac{16}{2}$

Divide $x$ by $1$ .

$x > \frac{16}{2}$

Simplify the right side.

Divide $16$ by $2$ .

$x > 8$

Find the intersection of $x < 4$ and $x > 8$ .

No solution