Solve for x log base 4 of x+5=3

$\log_{4} (x + 5) = 3$

Rewrite $\log_{4} (x + 5) = 3$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$4^{3} = x + 5$

Solve for $x$ .

Rewrite the equation as $x + 5 = 4^{3}$ .

$x + 5 = 4^{3}$

Raise $4$ to the power of $3$ .

$x + 5 = 64$

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$x = 64 - 5$

Subtract $5$ from $64$ .

$x = 59$

Solve for x log base 4 of x+5=3

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