Solve for x x/12+3<=7

$\frac{x}{12} + 3 \leq 7$

Step 1

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$\frac{x}{12} \leq 7 - 3$

Subtract $3$ from $7$ .

$\frac{x}{12} \leq 4$

Step 2

Multiply both sides by $12$ .

$\frac{x}{12} \cdot 12 \leq 4 \cdot 12$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{x}{12} \cdot 12 \leq 4 \cdot 12$

Rewrite the expression.

$x \leq 4 \cdot 12$

Simplify the right side.

Multiply $4$ by $12$ .

$x \leq 48$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \leq 48$

Interval Notation:

$(- \infty, 48]$