Solve the Absolute Value Inequality for x |2x+3|+4<5

$| 2 x + 3 | + 4 < 5$

Step 1

Write $| 2 x + 3 | + 4 < 5$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$2 x + 3 \geq 0$

Solve the inequality.

Subtract $3$ from both sides of the inequality.

$2 x \geq - 3$

Divide each term in $2 x \geq - 3$ by $2$ and simplify.

Divide each term in $2 x \geq - 3$ by $2$ .

$\frac{2 x}{2} \geq \frac{- 3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} \geq \frac{- 3}{2}$

Divide $x$ by $1$ .

$x \geq \frac{- 3}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x \geq - \frac{3}{2}$

In the piece where $2 x + 3$ is non-negative, remove the absolute value.

$2 x + 3 + 4 < 5$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$2 x + 3 < 0$

Solve the inequality.

Subtract $3$ from both sides of the inequality.

$2 x < - 3$

Divide each term in $2 x < - 3$ by $2$ and simplify.

Divide each term in $2 x < - 3$ by $2$ .

$\frac{2 x}{2} < \frac{- 3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} < \frac{- 3}{2}$

Divide $x$ by $1$ .

$x < \frac{- 3}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x < - \frac{3}{2}$

In the piece where $2 x + 3$ is negative, remove the absolute value and multiply by $- 1$ .

$- (2 x + 3) + 4 < 5$

Write as a piecewise.

${\begin{cases} 2 x + 3 + 4 < 5 & x \geq - \frac{3}{2} \\ - (2 x + 3) + 4 < 5 & x < - \frac{3}{2} \end{cases}$

Add $3$ and $4$ .

${\begin{cases} 2 x + 7 < 5 & x \geq - \frac{3}{2} \\ - (2 x + 3) + 4 < 5 & x < - \frac{3}{2} \end{cases}$

Simplify $- (2 x + 3) + 4 < 5$ .

Simplify each term.

Apply the distributive property.

${\begin{cases} 2 x + 7 < 5 & x \geq - \frac{3}{2} \\ - (2 x) - 1 \cdot 3 + 4 < 5 & x < - \frac{3}{2} \end{cases}$

Multiply $2$ by $- 1$ .

${\begin{cases} 2 x + 7 < 5 & x \geq - \frac{3}{2} \\ - 2 x - 1 \cdot 3 + 4 < 5 & x < - \frac{3}{2} \end{cases}$

Multiply $- 1$ by $3$ .

${\begin{cases} 2 x + 7 < 5 & x \geq - \frac{3}{2} \\ - 2 x - 3 + 4 < 5 & x < - \frac{3}{2} \end{cases}$

Add $- 3$ and $4$ .

${\begin{cases} 2 x + 7 < 5 & x \geq - \frac{3}{2} \\ - 2 x + 1 < 5 & x < - \frac{3}{2} \end{cases}$

Step 2

Solve $2 x + 7 < 5$ when $x \geq - \frac{3}{2}$ .

Solve $2 x + 7 < 5$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $7$ from both sides of the inequality.

$2 x < 5 - 7$

Subtract $7$ from $5$ .

$2 x < - 2$

Divide each term in $2 x < - 2$ by $2$ and simplify.

Divide each term in $2 x < - 2$ by $2$ .

$\frac{2 x}{2} < \frac{- 2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} < \frac{- 2}{2}$

Divide $x$ by $1$ .

$x < \frac{- 2}{2}$

Simplify the right side.

Divide $- 2$ by $2$ .

$x < - 1$

Find the intersection of $x < - 1$ and $x \geq - \frac{3}{2}$ .

$- \frac{3}{2} \leq x < - 1$

Step 3

Solve $- 2 x + 1 < 5$ when $x < - \frac{3}{2}$ .

Solve $- 2 x + 1 < 5$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$- 2 x < 5 - 1$

Subtract $1$ from $5$ .

$- 2 x < 4$

Divide each term in $- 2 x < 4$ by $- 2$ and simplify.

Divide each term in $- 2 x < 4$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} > \frac{4}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} > \frac{4}{- 2}$

Divide $x$ by $1$ .

$x > \frac{4}{- 2}$

Simplify the right side.

Divide $4$ by $- 2$ .

$x > - 2$

Find the intersection of $x > - 2$ and $x < - \frac{3}{2}$ .

$- 2 < x < - \frac{3}{2}$

Step 4

Find the union of the solutions.

$- 2 < x < - 1$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$- 2 < x < - 1$

Interval Notation:

$(- 2, - 1)$

Step 6

Solve the Absolute Value Inequality for x |2x+3|+4<5

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