Solve the Inequality for x -3+x<=-11

$- 3 + x \leq - 11$

Add $3$ to both sides of the inequality.

$x \leq - 11 + 3$

Add $- 11$ and $3$ .

$x \leq - 8$

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 8$

Interval Notation:

$(- \infty, - 8]$